a problem

posted by Shawn

Solve:
(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)

I do know that (t^2-t-56) can be factored out to (t-8)(t+7) so I have the equation as (t+24/(t-8)(t+7) +7(t+7)/(t-8)(t+7)-3(x-8)/(t-8)(t+7) is this correct ot what am I doing wrong?

  1. Writeacher

    Assistance needed.

  2. Shawn

    Solve:
    (t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)

    How do I solve this problem

  3. bobpursley

    the common denominator is (t-8)(t+7)

    so multipy both sides by

    (t-8)(t+7)

    (t-24) + 7(t+7)=3(t-8)
    solve for t.

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