posted by kelsey
A 8 kg crate is placed at rest on an incline plane (s=0.8, k=0.5), whose angle is 60o. It then slides 3 m down the incline.
work done by gravity: ?J
work done by friction force: ?J
Using your results from part a, find the speed of the crate after sliding this distance.
The normal force on the plane from weight is mgCosTheta. The component of force due to weight down the plane is mgSinTheta.
Work down the plane is Ffriction*distance, or mg*mu*SinTheta*distance.
Work done by gravity is mg*distancedownplane*SinTheta Think that out...