Algebra
posted by Anonymous .
Which equation could be used to find the dimensions of a room that has a length of 8 feet longer than the width, x, and has an area of 240 square feet?
(A) x squared  8x + 240 = 0
(B) 2x(2x8x+16)=240
(C) x squared + 8x + 240 = 0
(D) x squared + 8x  240 = 0
I got (x)(8x)=240 aka x squared + 8x = 240, which isn't any of the answer choices. I'm leaning towards (B) though, but I don't understand. Can someone please help me figure this one out? Thanks.

You should have started with Length times width.... (8+x)x=240

I know. That was a typo. So where do I go from there?