Chemistry

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calculate the wavelength of the second line in the Brackett series (nf=4) of the hydrogen emission spectrum. Rh= 2.180e-18

any help please? i know its energy levels 4 to 6... but that is all.

  • Chemistry -

    1/lambda= R (1/4^2-1/662) R= Rydberg constant = (1.09678E7 m^-1)

    A little algebra changes this to

    1/lambda= R (36-16)/(16*36)

    solve for lambda.

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