someone please chek my math!
posted by sam! .
a. An ellipse is formed by stretching the graph of x^2+ y^2=1 horizontally by a factor of 3 and vertically by a factor of 4. Determine the equation of the ellipse in standard form
x^2/a^2+y^2/b^2=1
(x/3) ^2+ (y/4) ^2=1
x^2/9 + y^2/16 =1
so the equation is:
x^2/9 + y^2/16 =1
b. The ellipse in question above is translated 4 units to the right and 2 units down. Determine the equations of this ellipse. Express your answer in both standard form and general form:
so the equation for standard form is:
(xh)^2/a^2 + (yk)^2/b^2=1
so
a: 9
b: 16
x: ?
Y?
h=4
k: 2
(x4) ^2/9^2 + (y2)^2/16^2=1
is this standard form right or am I wrong?
correct on both.
thanks bobpursley
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