What are the foci of the ellipse? Graph the ellipse.
18x2 + 36y2 = 648
the standard form of the equation is
x^2/36 + y^2/18 = 1
since a^2 = 36 and b^2 = 18 we have the foci at (±c,0)
where c^2 = a^2 - b^2 = 18
So the foci are at (±√18,0)
18x2 + 36y2 = 648
x^2/36 + y^2/18 = 1
since a^2 = 36 and b^2 = 18 we have the foci at (±c,0)
where c^2 = a^2 - b^2 = 18
So the foci are at (±√18,0)