statistic

Which set of points can be modeled without a power model? (2 points)
{(2.2, 4.33), (3.5, 6.641), (4.8, 10.184)}
{(1.4, 0.133), (2, 0.21), (2.6, 0.333)}
{(1.1, 17.155), (1.7, 14.941), (2.3, 13.013)}
{(1.4, 5.192), (1.8,6.104), (2.2, 7.016)}

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  1. {(1.4, 5.192), (1.8,6.104), (2.2, 7.016)}

    AB
    M =( 6.104-5.192)/(1.8-1.4) = 2.28
    Bc
    M = (7.016-6.104)/(2.2-1.8) = 2.28
    because slope is same

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