aluminum boat 14,5g volume 450cm3, how many pennies at 2.5g until boat sinks
Wt. = V * Dw
Wt. = 450cm^3 * 1g/cm^3 = 450 g = Max.
wt. without sinking.
14.5 + X = 450 Grams.
X = 435.5 grams can be added.
435.5/2.5 = 174.2 or 174 Pennies.
To figure out how many pennies it would take to sink an aluminum boat, we need to determine the weight of the boat and compare that to the weight of the pennies.
First, let's start by finding the weight of the boat. It is given that the aluminum boat weighs 14.5g.
Next, we need to determine the weight of the pennies. Each penny weighs 2.5g.
To calculate the maximum weight the boat can hold, we will subtract the weight of the boat from the weight of the pennies.
Weight of pennies needed = Weight of boat - Weight of pennies
Weight of pennies needed = 14.5g - 2.5g = 12g
Now, we need to calculate the number of pennies required. To do this, we'll divide the weight of the pennies needed by the weight of each penny.
Number of pennies = Weight of pennies needed / Weight of each penny
Number of pennies = 12g / 2.5g ≈ 4.8 pennies
Since we cannot have a fraction of a penny, we'll round up to the nearest whole number. Therefore, it would take approximately 5 pennies to sink the aluminum boat.