PHYSICS

The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 54.0 µT. A proton is moving horizontally towards the west in this field with a speed of 6.00 ✕ 106 m/s
What is the radius of the circular arc followed by this proton?
km

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  1. Isn't there a formula for this?

    you know B, and v, and q.

    calculate the force moving the proton inward, then set that equal to centripetal force , m v^2/r, calcualte r.

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    bobpursley

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