thanks for the help but i was wondering (16 square root of x-3) times(square root of x-1) is equal to 16x-19 square root of x then plus 3
No, it is not.
16 (sqrt (x-3) ) (sqrt (x-1))
if that is your problem. It is hard to determine from your text. Use parenthesis please.
16 (sqrt (x-3) ) (sqrt (x-1))
is the correct problem now how do u do that..sorry for the lack of paranthesees :(
No problem! Let's solve the problem step by step.
We have the expression: 16√(x-3) * √(x-1) = 16x - 19√x + 3
To solve this, we can use the distributive property of multiplication, which states that a(b+c) = ab + ac.
Applying the distributive property to the left side of the equation, we get: 16√(x-3) * √(x-1) = 16√x - 3(√(x-1))
Now let's simplify the right side of the equation: 16x - 19√x + 3
So, the equation becomes: 16√(x-3) * √(x-1) = 16√x - 3√(x-1)
Now, we can equate the two sides of the equation because they are equal:
16√x - 3√(x-1) = 16x - 19√x + 3
To solve for x, we need to isolate the square roots and simplify the equation further.
Start by moving all terms involving square roots to one side of the equation:
16√x + 19√x = 3√(x-1) + 16x - 3
Combine like terms:
35√x = 3√(x-1) + 16x - 3
Next, we need to square both sides of the equation to get rid of the square roots:
(35√x)^2 = (3√(x-1) + 16x - 3)^2
Simplifying further:
1225x = 9(x-1) + 96x^2 - 96x + 16x(x-1) - 6√(x-1) - 3√(x-1) + 48x - 9
Expanding and simplifying the right side:
1225x = 9x - 9 + 96x^2 - 96x + 16x^2 - 16x + 48x - 6√(x-1) - 3√(x-1) - 9
Combining like terms:
1225x = 16x^2 + 48x - 12√(x-1) - 18
Rearranging the equation:
16x^2 + (48x - 1225x) + 12√(x-1) - 18 = 0
Simplifying:
16x^2 - 1177x + 12√(x-1) - 18 = 0
Unfortunately, at this point in the calculations, we cannot solve for x algebraically because it is a quadratic equation combined with a square root term. It's likely that the original equation you provided may not be correct or that there may be a mistake in the steps above.
Please double-check your original equation or let me know if you need further assistance with a different problem.