Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Geometry
Triangles
3. The ratio of the altitude of a triangle to the length of its base is 5:12. Calculate the altitude if the length of the base is 42mm.
17.5
length/base= 5/12=x/42= 17.5
1 answer
Right.
You can
ask a new question
or
answer this question
.
Related Questions
The area of triangle ABC is divided into four equal parts by segments parallel to the base BC. The longest of these segments is
the vertex angle of an isoceles triangle is 120. the base length is 18. what is the length of the altitude to the base in
The area of a triangle is 600 square feet. Find the altitude, in feet, of the triangle if the length of the corresponding base
the ratio of the base of an isoceles triangle to one of the legs if the base is 10cm long and the leg is 4 cm less than twice
Each base of an isosceles triangle measures 42 degrees, 30'. The base is 14.6 meters long.
a. Find the length of a leg of the
the length of the base of a triangle is 4 times its altitude. if the area of a triangles is 162cm2 find the altitude
right triangle ABC with right angle C, AC=22 and BC=6, altitude CD where D is on hypotenuse AB. What is the ratio of the area of
The base is an equilateral triangle each side of which has length 10. The cross sections perpendicular to a given altitude of
The length of the base of an isosceles triangle is one fourth the length of one of its legs. If the perimeter of the triangle is
an altitude of triangle is 5/3rd of the length of its corresponding base if their altitude be increased by 4cm and the base is