John has used a solar simulator setup to measure the relation between the voltage and the current of a small photovoltaic cell (40 cm long and 40 cm wide). The measurement setup maintains the standard measurement conditions: the temperature is controlled to 25oC, the incident spectrum is the AM1.5 spectrum and the incident power density is 1000W/m2. The result is illustrated in the figure below.
Calculate the short-circuit current density (in mA/cm2).
John determined that the maximum power he could get out of this module is 19.5 W. Calculate the fill factor of the module (in %).
What is the efficiency of the module (in %)?
John decides to connect two of these modules with strips. This results in an additional 2mΩ series resistance loss. Which is the new fill factor (in %)? (Hint: use the voltage drop at the maximum power point).
first answer is 25
second answer: 81.25
third answer: 12.187
4th ans is 62.
Hi Ratan how did get 62 for the 4th answer?
Can you also give the rest of the answers?? thanx
Help on the rest???? Thanks
None of the other answers are 6...
Someone can give me a hand?
Just need the last one now....Someone???? the fourth answer
someone can help???
Solar simulators are used to study the performance of solar cells in the lab. In the figure below (left picture), the spectral power density of a solar simulator is shown with the blue line. The spectral power density of this solar simulator is given by:
P(λ)=7.5∗1015λ−2.25∗109 [Wm−2m−1] for 300nm<λ<500nm
P(λ)=2.25∗109−1.5∗1015λ [Wm−2m−1] for 500nm<λ<1500nm
Where the wavelength λ is expressed in meters.
a) calculate the irradiation I of the solar simulator (in Wm−2 )
incorrect
b) What is the photon flux of the solar simulator (in 1021m−2s−1)?
1. 25
2. 81.25
3. 12.187
4. 62