In the first 3.8 seconds of a bobsled run, the 57 kg sled is pushed until it reaches a speed of 1.1 m/s. The flat surface has a coefficient of friction of 0.06. What is the acceleration of the sled in this time? What constant force is exerted by the bobsled team?
a = V/t = (1.1m/s)/3.8s = 0.2895 m/s^2.
Ws = m * g = 57kg * 9.8N/kg = 558.6 N.=
Weight of the sled.
Fex - Ff = m * a
Fex - 0.06*558.6 = 57*0.2895
Fex - 33.52 = 16.5
Fex = 16.5 + 33.52 = 50.0 N. = Force
exerted.
To find the acceleration of the sled, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
Step 1: Calculate the net force acting on the sled.
The net force can be determined by subtracting the force of friction from the applied force.
The force of friction can be calculated using the equation: force of friction = coefficient of friction * normal force.
The normal force is equal to the weight, which is calculated as mass * gravity.
Normal force = mass * gravity = 57 kg * 9.8 m/s^2 ≈ 558.6 N
Force of friction = coefficient of friction * normal force = 0.06 * 558.6 N ≈ 33.5 N
Step 2: Calculate the applied force.
The applied force can be determined by using the equation: force = mass * acceleration.
We need to rearrange the equation to solve for acceleration: acceleration = force / mass.
Acceleration = applied force / mass
We need to find the applied force, so we rearrange the equation: applied force = acceleration * mass.
Now, we substitute the known values to find the applied force:
Applied force = (1.1 m/s) * 57 kg ≈ 62.7 N
Therefore, the acceleration of the sled is 1.1 m/s^2, and the constant force exerted by the bobsled team is approximately 62.7 N.