Table salt NaCl and sugar C12H22O11 are accidentally mixed. A 6.00 g sample is burned and 2.90 g of CO2 is produced. What was the mass percentage of the table salt mixture?
Could you please show me all the way through if you can?
Yes, I can help you with that.
To find the mass percentage of the table salt mixture, we need to determine the mass of NaCl in the mixture first.
Let's start by calculating the moles of CO2 produced during the combustion.
The balanced chemical equation for the combustion of sugar (C12H22O11) is:
C12H22O11 + 12O2 -> 12CO2 + 11H2O
From this equation, we can see that the ratio between C12H22O11 and CO2 is 1:12.
Given that 2.90 g of CO2 is produced, we can calculate the moles of CO2:
moles of CO2 = mass of CO2 / molar mass of CO2
The molar mass of CO2 is 44.01 g/mol, so:
moles of CO2 = 2.90 g / 44.01 g/mol
Now, since the ratio between C12H22O11 and CO2 is 1:12, the moles of C12H22O11 will be:
moles of C12H22O11 = moles of CO2 / 12
Next, we can calculate the moles of NaCl based on the moles of CO2.
The balanced chemical equation for the combustion of NaCl is:
2NaCl + O2 -> 2NaClO
From this equation, we can see that the ratio between NaCl and CO2 is 2:2.
Therefore, the moles of NaCl will be equal to the moles of CO2.
Now, we can calculate the mass of NaCl:
mass of NaCl = moles of NaCl x molar mass of NaCl
The molar mass of NaCl is 58.44 g/mol.
Finally, we can calculate the mass percentage of NaCl in the mixture:
mass percentage of NaCl = (mass of NaCl / mass of mixture) x 100
The mass of the mixture is given as 6.00 g.
Now, you can follow these calculations step-by-step to determine the mass percentage of the table salt mixture.
Sure! To determine the mass percentage of the table salt mixture, we need to find the mass of the salt in the mixture.
First, let's calculate the molar mass of CO2 (carbon dioxide). The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Since CO2 has one carbon atom and two oxygen atoms, its molar mass is:
Molar mass of CO2 = (12.01 g/mol) + 2 * (16.00 g/mol) = 44.01 g/mol
Now, we can use the mass of CO2 produced (2.90 g) to find the number of moles produced:
Number of moles of CO2 = Mass of CO2 / Molar mass of CO2 = 2.90 g / 44.01 g/mol = 0.0659 mol
Since the reaction ratio between salt and CO2 is 1:1, the number of moles of salt in the mixture is also 0.0659 mol.
To find the mass of the salt in the mixture, we need to use the molar mass of sodium chloride (NaCl). The molar mass of sodium (Na) is 22.99 g/mol and the molar mass of chlorine (Cl) is 35.45 g/mol. The molar mass of NaCl is:
Molar mass of NaCl = (22.99 g/mol) + (35.45 g/mol) = 58.44 g/mol
Now, we can calculate the mass of the salt in the mixture:
Mass of salt = Number of moles of salt x Molar mass of NaCl = 0.0659 mol x 58.44 g/mol = 3.84 g
Finally, we can calculate the mass percentage of the salt in the mixture:
Mass percentage of salt = (Mass of salt / Mass of the mixture) x 100% = (3.84 g / 6.00 g) x 100% = 64.0%
Therefore, the mass percentage of the table salt mixture is approximately 64.0%.
NaCl doesn't burn. Sugar does.
C12H22O11 + 12O2 ==> 12CO2 + 11H2O
Convert g CO2 to mols sugar.
2.90g CO2 x (molar mass sugar/12*molar mass CO2) = 2.90 x (342/12*44) = about 1.9
NaCl + sugar = 6.00
mass sugar = -1.9
mass NaCl = 6-1.9 about 4.1
%NaCl = (mass NaCl/mass sample)*100 = ?
%NaCl = about (4.1/6)*100 = about 68.7%
You should go through and do it more accurately. I've just estimated here and ther.