5 students are trying out for the debate team. There are 3 available spots for the team.How many combinations of teams can the debate team make
My answer is 15 am i right? If not please tell me your answer and how you got it
I think you're right, but I'm not sure.
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There are 10 choices
This is a "combination" type question, since the order of the selection does not matter.
It would be C(5,3) = 5!/(3!2!) = 10
Thanks, Reiny.
To find the number of combinations of teams that can be made, we can use the formula for combinations. In this case, we have 5 students trying out for 3 available spots on the team.
The formula for combinations is: nCr = n! / (r!(n-r)!)
Where n is the number of students (5 in this case) and r is the number of spots available on the team (3 in this case).
Using the formula, we can calculate the number of combinations:
5! / (3!(5-3)!)
= 5! / (3! * 2!)
= (5 * 4 * 3!) / (3! * 2 * 1)
= (5 * 4) / (2 * 1)
= 20 / 2
= 10
So, there are 10 different combinations of teams that the debate team can make.