Can I get help on just 3 questions?
-6x + (1 - 3x) x 8
(r-1) x -3 - 3
(n-4) x -7 +7
Thanks
Are your x's multiplication signs or unknowns?
We use * to indicate multiplication.
Multiplication signs. Sorry :(
-6x + (1 - 3x) x 8 -- Doesn't make sense.
(r-1) x -3 - 3 = -6r + 6
(n-4) x -7 +7 = 0
umm.. it is -6x + (1 - 3x) * 8
Why do you have a multiplication sign and an addition sign next to each other?
-6x +
The x is a variable put into the equation so it would be -6x + (plus) (1 - 3x) * 8
Of course! I'd be happy to help you with those three questions. Let's go through each one step by step.
Question 1: -6x + (1 - 3x) x 8
To solve this expression, we need to simplify it using the order of operations, which is often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, and Addition and Subtraction from left to right).
First, let's simplify the expression inside the parentheses: (1 - 3x).
To do this, we distribute the 8 to both terms inside the parentheses:
1 x 8 = 8
-3x x 8 = -24x
So, the expression becomes: -6x + (8 - 24x).
Now, let's simplify further:
-6x + 8 - 24x = -30x + 8
Question 2: (r-1) x -3 - 3
We can solve this question using the same steps as above.
First, let's simplify the expression inside the parentheses: (r-1).
Now, distribute the -3 to both terms inside the parentheses:
r x -3 = -3r
-1 x -3 = 3
So, the expression becomes: -3r + 3 - 3.
Now, let's simplify further:
-3r + 3 - 3 = -3r
Question 3: (n-4) x -7 + 7
Again, we can solve this question using the same steps as above.
First, let's simplify the expression inside the parentheses: (n-4).
Now, distribute the -7 to both terms inside the parentheses:
n x -7 = -7n
-4 x -7 = 28
So, the expression becomes: -7n + 28 + 7.
Now, let's simplify further:
-7n + 28 + 7 = -7n + 35
Therefore, the simplified forms of the three expressions are:
1. -6x + (1 - 3x) x 8 = -30x + 8
2. (r-1) x -3 - 3 = -3r
3. (n-4) x -7 + 7 = -7n + 35
I hope this explanation helps you understand how to approach these questions! If you have any further questions, feel free to ask.