can someone show me steps for this
the product of (6x+9)(x^2-4x+5)
( 6 x + 9 ) ( x ^ 2 - 4 x + 5 ) =
6 x * x ^ 2 + 9 * x ^ 2 + 6 x * ( - 4 x ) + 9 * ( - 4 x ) + 6 x * 5 + 9 * 5 =
6 x ^ 3 + 9 x ^ 2 - 24 x ^ 2 - 36 x + 30 x + 45 =
6 x ^ 3 - 15 x ^ 2 - 6 x + 45 =
3 ( 2 x ^ 2 - 5 x - 2 x + 15 )
visit calc101.com and click on the "long multiplication" button. It will show all the messy details.
Sure! I can help you with that. To find the product of (6x+9)(x^2-4x+5), we can use the distributive property.
Step 1: Multiply the first term of the first expression (6x) by each term of the second expression (x^2-4x+5).
(6x) * (x^2) = 6x^3
(6x) * (-4x) = -24x^2
(6x) * (5) = 30x
Step 2: Multiply the second term of the first expression (+9) by each term of the second expression (x^2-4x+5).
(9) * (x^2) = 9x^2
(9) * (-4x) = -36x
(9) * (5) = 45
Step 3: Combine all the terms obtained from the previous steps.
6x^3 - 24x^2 + 30x + 9x^2 - 36x + 45
Step 4: Simplify the expression by combining like terms.
The like terms here are the ones with the same powers of x:
6x^3 + (-24x^2 + 9x^2) + (30x - 36x) + 45
This simplifies to:
6x^3 - 15x^2 - 6x + 45
And that's the product of (6x+9)(x^2-4x+5)!