# Pure Mathematics

Find the modulus and principal argument of the complex numbers giving the argument in radians either as pi or a decimal correct to 2 decimal places

c) i square root 3 -2 ALL UPON -2-i square root 3

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1. (-2 + √3i)/(-2 - √3i)

recall that (a+bi)(a-bi) = a^2+b^2
Use that to get rid of the complex number in the bottom:

(-2+√3i)/(-2-√3i) * (-2+√3i)/(-2+√3i)

(-2+√3i)^2 / (4+3)

(4-4√3i-3)/7
1/7 - 4√3/7 i

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2. THANKS!! now I can find the modulus and argument
=D

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