How many stereoisomers are possible for each of the following structures? Draw them, and name each by the R-S and E-Z conventions

To determine the number of stereoisomers for a molecule and name them using the R-S and E-Z conventions, we need to consider the presence of chiral centers and double bonds in the molecule. Let's investigate each structure separately:

1. Chiral center(s) without double bond(s):
For a molecule with n chiral centers, the maximum number of stereoisomers is determined by 2^n.
- Draw the structure and identify the chiral centers.
- Assign priorities to the substituents attached to each chiral center based on atomic number.
- Determine the R or S configuration for each chiral center based on the Cahn-Ingold-Prelog sequence rules.
- Name each stereoisomer conventionally using the R-S notation.

2. Double bond(s) without chiral center(s):
For a molecule with n double bonds, the maximum number of stereoisomers is determined by 2^n.
- Draw the structure and identify the double bonds.
- Assign priorities to the substituents attached to each carbon of the double bond.
- Determine the E or Z configuration for each double bond based on the Cahn-Ingold-Prelog sequence rules.
- Name each stereoisomer using the E-Z notation.

3. Chiral center(s) and double bond(s) combined:
In this case, the total number of stereoisomers is the product of the individual possibilities for chiral centers and double bonds.
- Draw the structure and identify both the chiral centers and double bonds.
- Apply the procedures mentioned above separately for chiral centers and double bonds.
- Multiply the number of possibilities for chiral centers with the number of possibilities for double bonds to get the total number of stereoisomers.
- Name each stereoisomer using the combined R-S and E-Z notations.

Unfortunately, the specific structures were not mentioned in your question. If you provide the structures, I would be happy to guide you further on how to determine the number of stereoisomers and name them using the R-S and E-Z conventions.