physics

A bus accelerates from rest at 1.5m/s^2 for 12s. It then travels for 25s after which it slows to a stop with an acceleration of magnitude 1.5m/s^2. (a) Find the total distance the bus travels And its average velocity of the trip.

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asked by robert
  1. A bus accelerates from rest at 1.5m/s^2 for 12s. It then travels for 25s after which it slows to a stop with an acceleration of magnitude 1.5m/s^2. (a) Find the total distance the bus travel snd its average velocity of the trip.

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    posted by robert
  2. 666 meters

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    posted by robert
  3. x1 = (1/2)(1.5)(12^2) = 108 m
    v1 = 1.5(12) = 18 m/s

    x2 = 108 + 18(25) = 558 m
    v2 = v1 = 18

    x3 = 558 + 18 t - (1/2)1.5 t^2
    v3 = 0
    = 18 - 1.5 t
    so t = 12 seconds to stop (of course)
    then
    x3 = 558 + 18(12) - (1/2)(1.5)(144)
    = 558 + 216 - 108
    = 666 meters

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    posted by Damon
  4. a devil of a problem!

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    posted by Steve

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