A 12 g sample of iron ore is treated as follows. The iron in the sample is all converted by a series of chemical reactions to Fe2O3. The mass of Fe2O3 is measured to be 27.6 g. What was the mass of iron in the sample of ore?
Answer in units of g
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actually they aren't this is the question exactly as i got it off my worksheet.
To find the mass of iron in the sample of ore, we can use the information given about the mass of Fe2O3 and the original sample of iron ore.
1. Start by subtracting the mass of Fe2O3 from the total mass of the sample to determine the mass of oxygen in the Fe2O3.
Mass of oxygen = Total mass of Fe2O3 - Mass of Fe2O3
Mass of oxygen = 27.6 g - 12 g
2. Next, we need to find the molar mass of Fe2O3. The molar mass is the mass of one mole of a substance, and it is calculated by adding up the atomic masses of each element in the compound.
Molar mass of Fe2O3 = (2 x atomic mass of Fe) + (3 x atomic mass of O)
Molar mass of Fe2O3 = (2 x 55.85 g/mol) + (3 x 16.00 g/mol) = 159.70 g/mol
3. Now, we can calculate the number of moles of Fe2O3 by dividing the mass of Fe2O3 by its molar mass.
Moles of Fe2O3 = Mass of Fe2O3 / Molar mass of Fe2O3
Moles of Fe2O3 = 27.6 g / 159.70 g/mol
4. From the balanced chemical equation, we know that 1 mole of Fe2O3 contains 2 moles of Fe. Therefore, we can calculate the number of moles of Fe in the sample.
Moles of Fe = 2 x Moles of Fe2O3
5. Finally, to find the mass of iron in the sample, we can multiply the number of moles of Fe by the molar mass of iron.
Mass of iron = Moles of Fe x Atomic mass of Fe
Now plug in the values we have obtained:
Mass of iron = (2 x (27.6 g / 159.70 g/mol)) x 55.85 g/mol
Calculating this expression will give you the mass of iron in the sample of ore.