in the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. If 4.59 mol of magnesium and 4.59 mol of hydrochloric acid are reacted, how many moles of magnesium chloride are produced ?
The equation is
Mg + 2HCl ==> MgCl2 + H2
Follow your post above on limiting reagent problems but use the above equation and you can skip steps a and b.
Post your work if you get stuck.
To determine the number of moles of magnesium chloride produced, we need to first identify the balanced chemical equation for the reaction between magnesium and hydrochloric acid.
The balanced equation for the reaction is:
Mg + 2HCl → MgCl2 + H2
From the equation, we can see that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of magnesium chloride and 1 mole of hydrogen gas.
Given that 4.59 moles of magnesium and 4.59 moles of hydrochloric acid are reacted, we can use the ratio from the balanced equation to determine the number of moles of magnesium chloride produced.
Since 1 mole of magnesium reacts with 2 moles of hydrochloric acid, and the amount of hydrochloric acid is the same as the amount of magnesium, we can conclude that 4.59 moles of magnesium will react with 2 * 4.59 = 9.18 moles of hydrochloric acid.
Since the ratio of moles of magnesium to moles of magnesium chloride is 1:1, we can conclude that 4.59 moles of magnesium chloride will be produced.
Therefore, the number of moles of magnesium chloride produced is 4.59 moles.