According to the equation

CH3COOH + NaOH ---> NaCH3COO + H2O

is the the ratio in which the acid and the base react 1:1?

How can I calculate the molar concentration of the acetic acid from this information?

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  1. Ues, on a mole basis. 1:1

    You cannot calculate the concentration of the acetic acid unless you know somethine else.

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