(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 8.02 m/s when going down a slope for 4.28 s? (b) How far does the skier travel in this time?
v=u+ft or 8.02=0+fx4.28
f=8.02/4.28=1.81m/s^2
v^2=u^2+2fs or 8.02^2=0+2x1.81xs
s=8.02^2/2x1.81=17.77m