A box contains 4 tickets letter O, A, G, C. Two tickets will randomly be selected without replacement.
What is the probability of selecting O then A in that order?
probability of O = 1/4
then probability of A = 1/3
(1/4)(1/3) = 1/12
What is the probability of selecting O then A in that order?
then probability of A = 1/3
(1/4)(1/3) = 1/12