a mixture of alcohol and water is 35% acid. if the mixture contains a total of 40L, How many liters of pure acid are in the mixture? how many liters of pure water are in the mixture?
40L * .35 = 14L acid
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To find the number of liters of pure acid and pure water in the mixture, we need to start by understanding that the percentage provided refers to the concentration of acid in the mixture.
Let's break down the problem into steps:
Step 1: Calculate the amount of acid in the mixture.
Since the mixture is 35% acid, it means that for every 100 parts of the mixture, 35 parts consist of acid. Therefore, the amount of acid in the mixture can be calculated as:
Amount of acid = 35% of 40L
Amount of acid = (35/100) * 40L
Amount of acid = 14L
So, there are 14 liters of pure acid in the mixture.
Step 2: Calculate the amount of water in the mixture.
Since the total volume of the mixture is 40L and we know that there are 14L of pure acid, we can subtract the amount of acid from the total volume to find the amount of water:
Amount of water = Total volume - Amount of acid
Amount of water = 40L - 14L = 26L
Therefore, there are 26 liters of pure water in the mixture.
In summary:
- There are 14 liters of pure acid in the mixture.
- There are 26 liters of pure water in the mixture.