Three pools are being drained for the winter. It takes Pool B twice as long to drain compared to Pool A, and it takes
Pool B three times as long to drain compared to Pool C. If Pool C drains in 6 hours, which of the following is the
number of hours it takes Pool A to drain
pool C drains in 6 hrs
pool B drains in 18 hrs (took 3 times as long)
pool A drains in 9 hrs ( B's time was twice A's time)
Just follow the wording of the question.
Let's use some variables to represent the time it takes each pool to drain:
Let's say:
- The time it takes for Pool A to drain is represented by "x" hours.
- The time it takes for Pool B to drain is represented by "2x" hours since it takes twice as long as Pool A.
- The time it takes for Pool C to drain is represented by 6 hours.
Now, we know that Pool B takes three times as long to drain compared to Pool C. So, we can write the equation:
2x = 3 * 6
Simplifying the equation:
2x = 18
To find the value of x, we can divide both sides of the equation by 2:
x = 18 / 2
x = 9
Therefore, it takes Pool A 9 hours to drain.
To find out how long it takes Pool A to drain, we need to compare its draining time to the other pools.
We are given that Pool B takes twice as long as Pool A to drain, and Pool C takes three times as long as Pool B to drain.
Let's assign variables to represent the draining times:
Let's say Pool A takes x hours to drain.
Pool B takes 2x hours to drain (twice as long as Pool A).
Pool C takes 3(2x) = 6x hours to drain (three times as long as Pool B).
Given that Pool C takes 6 hours to drain, we can set up the equation:
6x = 6
To solve for x (the time it takes for Pool A to drain), we divide both sides of the equation by 6:
6x/6 = 6/6
x = 1
Therefore, Pool A takes 1 hour to drain.