Find an equation for the ellipse described.
center(0,0); major axis horizontal with length10; length of minor axis is 8
x^2/5^2 + y^2/4^2 = 1
To find an equation for the given ellipse, we can use the standard form of the equation for an ellipse:
((x - h)^2 / a^2) + ((y - k)^2 / b^2) = 1
Where (h, k) represents the center of the ellipse, 'a' is the length of the semi-major axis, and 'b' is the length of the semi-minor axis.
Given that the center is (0, 0), the semi-major axis has a length of 10 (which means the major axis has a length of 2a = 20), and the semi-minor axis has a length of 8, we can substitute these values into the equation:
((x - 0)^2 / 10^2) + ((y - 0)^2 / 8^2) = 1
Simplifying further:
x^2 / 100 + y^2 / 64 = 1
So, the equation for the given ellipse is:
x^2 / 100 + y^2 / 64 = 1