1. x^9 over x^2 (1 point)

x^11
x^7
7
x^5
2. H^14 over h^5 (1 point)
h^-9
1 over h^9
h^19
h^9
3. 4^4 over 4^6 (1point)
–16
16
1/16
–1/16
4. 50 (1 point)
0
5
1
–5

Please I barely understand this but Ima try to put in what I think it is.

MY answers:
1. x^11
2. h^19
3. I am not exactly sure but is it 16???
4. 5

You have these all exactly backward

If you know how to reduce fractions, you know that

5*5*5*5*5/5*5*5 = 5*5

That is, 5^5/5^3 = 5^2, NOT 5^8
When multiplying, add exponents
When dividing, subtract exponents

x^9/x^2 = x^7, not x^11

Now try the others.
For the last, if it's multiplication, 5*0 = 0
anything*0 = 0

okay so 4 is Zero. But the other ones I am still lost.

x^9/x^2

is just a short way of writing
x•x•x•x•x•x•x•x•x/x•x
You can cancel out the x•x top and bottom leaving just
x•x•x•x•x•x•x

you started out with 9 x's, and after cancelling 2 of them, you have just 7 left.

Just as you reduce fractions,

15/70 = 3*5/2*5*7 you can cancel out the 5 leaving
3/14

Canceling out the same factor top and bottom just means subtracting 1 from each exponent. Once you get to a zero exponent somewhere, you're done, since x^0 = 1

h^14 / h^5 = h^5*h^9 / h^5 = h^9
Note that 9=14-5

4^4/4^6 = 4^4/(4^4*4^2) = 1/4^2 = 1/16
That means that 4^-2 = 1/4^2 = 1/16
Negative exponents are reciprocals.

Soo number one would be x^7?

yes, as I explicitly stated above.

Alright what about 2 and three?

did you actually read what I posted above?

Well I am better at working out the problem with someone.

Be careful, Balla. You're skating on thin ice.

I am? *gulp* oh boy.. I really have to be careful. But I was really serous though. I can understand things better when I work them out one by one rather then just reading something and then just solving. Do you know what I mean? I guess I am a visual learner and the type of learner that starts with a k.