hurry!, find the value of x in 2^x + 2^x + 2^x = 192. with explanation.
2 ^ x + 2 ^ x + 2 ^ x = 192
3 * 2 ^ x = 192 Divide both sides by 3
3 * 2 ^ x / 3 = 192 / 3
2 ^ x = 64
x = 6 becouse 2 ^ 6 = 64
OR
2 ^ x = 64
x * log ( 2 ) = log ( 64 ) Divide both sides by log ( 2 )
x = log ( 64 ) / log ( 2 )
x = 4.158883 / 0.693147
x = 6
log ( x ) is " Natural logarithm " ( Logarithm with base e )
x =