# chemistry

Im really sorry I got sidetracked:P This is the question I wanted to ask you

In a saturated solution of silver sulfite, the concentration of silver ion is 3.6 x 10^-4 mol/L. The Ksp of silver sulfite willl be what?

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1. Do you mean silver sulfite or silver sulfide. I will assume you mean what you wrote. Nothing will change, except the formula, if it is Ag2S.
Ag2SO3 ==> 2Ag^+ + SO3=
Ksp = (Ag^+)^2(SO3^=)
(Ag^+) = 3.6 x 10^-4 from the problem.
(SO3^=) = 1/2 that.
Plug into the Ksp expression and calculate Ksp.

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posted by DrBob222
2. Ksp = [SO3][Ag]^2 / [Ag2SO3]

= [1.8 x 10^-4][3.6 x 10^-4]^2 /
[ ]

Would I divide by 1.8 x 10^-4 since there is one mole of Ag2So3?

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posted by MikeSo
3. Ksp = (Ag^+)^2(SOc^=).
The denominator is 1, not (Ag2SO3).
This is not an equilibrium constant. No Ksp has anything on the bottom except 1.

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posted by DrBob222
4. AHHH help i have no idea!!!

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posted by sasha
5. KSP for Au2 S

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