A 1.00-kg ball is attached to a string of 0.50 m and swung in a horizontal circle with a velocity of 2.00 m/s. Find the centripetal acceleration.
ac=v^2/r
= 2.00^2/.50
= 8.0 m/s^2
didn't I answer this already? A horizontal circle with the string parallel to the Earth can only be attained in a gravity free environment
the reposts are all ones that werent answered yesterday that I asked
Well, well, well, spinning in circles, are we? I'm sorry, I couldn't resist a little joke. But hey, let's get to the math!
You're absolutely right, my friend! The centripetal acceleration, or ac, can be found using the formula ac = v^2/r. Plugging in the values, we have:
ac = 2.00^2 / 0.50
= 4.00 / 0.50
= 8.0 m/s^2
So, there you have it, a centripetal acceleration of 8.0 m/s^2 for our ball swinging around in a horizontal circle. Keep spinning and keep calculating!
To find the centripetal acceleration, you can use the equation ac = v^2/r, where ac represents the centripetal acceleration, v is the velocity, and r is the radius of the circle.
Given:
Mass of the ball (m) = 1.00 kg
Radius of the circle (r) = 0.50 m
Velocity (v) = 2.00 m/s
Using the formula ac = v^2/r, substitute the given values:
ac = (2.00 m/s)^2 / (0.50 m)
ac = 4.00 m^2/s^2 / 0.50 m
ac = 8.00 m/s^2
Therefore, the centripetal acceleration is 8.00 m/s^2.
To find the centripetal acceleration of a ball being swung in a horizontal circle, you can use the formula: ac = v^2/r, where ac is the centripetal acceleration, v is the velocity of the ball, and r is the radius of the circle.
In this case, the velocity (v) is given as 2.00 m/s, and the radius (r) is given as 0.50 m. Plugging these values into the formula, we get:
ac = (2.00^2) / 0.50 = 4.00 / 0.50 = 8.0 m/s^2
Therefore, the centripetal acceleration of the ball is 8.0 m/s^2.