I need 2 three digit numbers that total 16848
Do you mean a three digit number whose digits' product is 16848?
I'm sorry, but I don't think this is possible since 999 + 999 = 1098 (even the sum of the largest possible three-digit numbers do not give us a large enough total. 104 x 162 = 16848 (not sure if you wanted a "product?" I found this by trial and error with a calculator). I hope this helps you. Good luck!
To find two three-digit numbers that add up to 16848, we can follow these steps:
Step 1: Let's assume the two numbers as "x" and "y".
Step 2: Since both numbers are three-digit numbers, we can express them as:
x = 100a + 10b + c
y = 100p + 10q + r
Here, "a", "b", "c", "p", "q", and "r" represent individual digits.
Step 3: Now, we can express the equation as:
x + y = 16848
Substitute the values of x and y from step 2 into the equation:
100a + 10b + c + 100p + 10q + r = 16848
Simplifying this equation further, we get:
100(a + p) + 10(b + q) + (c + r) = 16848
Step 4: Since we want three-digit numbers, "a + p" must be equal to 1. (as 1 is the only digit that gives a three-digit result when multiplied by 100)
Therefore, a + p = 1
One possible option for "a" and "p" is 0 and 1, respectively.
Step 5: Substitute the values of a and p into the equation:
100(0) + 10(b + q) + (c + r) = 16848
Simplifying this equation further:
10(b + q) + (c + r) = 16848
Step 6: Now, we need to find values for "b" and "q" which sum up to 3. (as a single-digit number multiplied by 10 gives the sum of 3)
Therefore, b + q = 3
Possible values for b and q are:
b = 2 and q = 1
b = 3 and q = 0
b = 4 and q = -1 (not possible since it is a negative value)
Step 7: Substitute the values of b and q into the equation:
10(2) + (c + r) = 16848
10(3) + (c + r) = 16848
Simplifying these equations further:
20 + (c + r) = 16848
30 + (c + r) = 16848
Step 8: Solve for (c + r) in both equations:
(c + r) = 16848 - 20
= 16828
(c + r) = 16848 - 30
= 16818
Step 9: Now, we need to find two values for "c" and "r" which sum up to the numbers we just got.
For (c + r) = 16828:
One possible option is c = 1 and r = 6828.
For (c + r) = 16818:
One possible option is c = 2 and r = 6816.
Step 10: Substitute the values of a, b, c, p, q, and r into the original equations from step 2:
x = 100(0) + 10(2) + 1
= 21
y = 100(1) + 10(1) + 6828
= 16829
x = 100(0) + 10(3) + 2
= 32
y = 100(1) + 10(0) + 6816
= 6916
Therefore, two three-digit numbers that add up to 16848 are 21 and 16829, or 32 and 6916.