Selma went to the mall spent 1/3 of her money. she then lost 1/2 of what she had left. she then had $6. how much money did selma originally have.
Let x = original amount.
x - (1/3x) - (1/2)(2/3x) = 6
Solve for x.
she had 18 bucks to start with,
x=starting amount
x(2/3)(1/2) = 6
To find out how much money Selma originally had, we can work backward from the given information.
Let's start by representing Selma's original amount of money as "x".
According to the information provided:
1. Selma spent 1/3 of her money, which means she had (2/3)x remaining.
2. She then lost 1/2 of what she had left, which leaves her with (1/2)(2/3)x = (1/3)x.
3. Finally, it is mentioned that she had $6 remaining, which means (1/3)x = $6.
To solve for x, we'll isolate it by multiplying both sides of the equation by the reciprocal of 1/3, which is 3/1 (or just 3).
(1/3)x = $6
x = $6 * (3/1)
x = $18
Therefore, Selma originally had $18.