HELP Physics

The average rate at which energy is conducted outward through the ground surface in a certain region is 30.9 mW/m2, and the average thermal conductivity of the near-surface rocks is 3.11 W/m·K. Assuming a surface temperature of 9.48°C, find the temperature (in Celsius) at a depth of 35.0 km (near the base of the crust). Ignore the heat generated by the presence of radioactive elements.

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asked by Shane
  1. heatflow= conductivity*Area/depth*deltaTemp

    heatflow/area=conductivity/depth*(Surfacetemp-lowertemp)

    solve for lower temp

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