Calcualate the volume of 0.300mol of gas at 60 degrees C and 0.821atm.
The local atmospheric pressure is 560 mm Hg. what is the pressure in pascals? Do you think you are at sea level or higher than sea level?
1 atm = 760 mm Hg.
101,325 Pascals (Pa) = 1 atm.
hes a big chunky boi
PV=nRT eq........1
Here P=0.821atm
That's why we take value of R which is 0.0821
Then put the value in the eq.........1. You will get the answer
To calculate the volume of a gas, you can use the ideal gas law equation: PV = nRT.
In this equation:
- P represents the pressure of the gas
- V represents the volume of the gas
- n represents the number of moles of the gas
- R is the ideal gas constant (0.0821 L·atm/(mol·K) under standard conditions)
- T represents the temperature of the gas in Kelvin
To solve for V, we need to rearrange the equation as follows:
V = (nRT) / P
Given:
- n = 0.300 mol (number of moles)
- T = 60 degrees C = 60 + 273.15 = 333.15 K (convert to Kelvin)
- P = 0.821 atm (pressure)
Substituting these values into the equation, we get:
V = (0.300 mol * 0.0821 L·atm/(mol·K) * 333.15 K) / 0.821 atm
Now we can calculate the volume by performing the math:
V = (0.300 * 0.0821 * 333.15) / 0.821
V ≈ 9.476 L
Therefore, the volume of 0.300 mol of gas at 60 degrees C and 0.821 atm is approximately 9.476 L.