Physics

A 3.6 kg ball strikes a wall with a velocity of 9.3 m/s. The ball bounces off with a velocity of 7.9 m/s in the opposite direction. If the ball is in contact with the wall for 0.4 seconds, what is the constant force exerted on the ball by the wall?

asked by Sam
  1. force*time=mass(changeinvelocity)
    = mass(Vf-Vi)
    = mass(7.9+9.3)
    solve now for force.

    Notice the sign change in velocity, that is what OPPOSITE direction is, a sign change.

    posted by bobpursley

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