the ka of hypochlorous acid hclo is 3.5 x 10^-8. What is Kb for the hypochlorite ion?
2.8
To find Kb for the hypochlorite ion, we can use the relationship between Ka and Kb:
Ka × Kb = Kw
Where Kw is the ion product constant for water at a given temperature, which is equal to 1.0 x 10^-14.
We can rearrange the equation to solve for Kb:
Kb = Kw / Ka
Substituting the given value for Ka:
Kb = (1.0 x 10^-14) / (3.5 x 10^-8)
Now, let's calculate Kb:
Kb ≈ 2.86 x 10^-7
Therefore, Kb for the hypochlorite ion (ClO-) is approximately 2.86 x 10^-7.
To find Kb for the hypochlorite ion (ClO-), we can use the relationship between Ka and Kb for a conjugate acid-base pair.
The Ka expression for hypochlorous acid (HClO) is:
Ka = [H+][ClO-] / [HClO]
Since we know the value of Ka for HClO (3.5 x 10^-8), we can rearrange this equation to solve for [ClO-]:
[ClO-] = (Ka * [HClO]) / [H+]
Now, the Kb expression for the hypochlorite ion (ClO-) is:
Kb = [OH-][HClO] / [ClO-]
We can use the fact that Kw (the water dissociation constant) is equal to [H+][OH-] = 1.0 x 10^-14, to substitute [OH-]:
[OH-] = Kw / [H+]
Now we can substitute these values into the Kb expression for ClO-:
Kb = ([H+][OH-][HClO]) / [ClO-]
= ([H+][OH-][HClO]) / ((Ka * [HClO]) / [H+])
= (Kw * [H+]) / Ka
Now, we can plug in the known values:
Kw = 1.0 x 10^-14
Ka = 3.5 x 10^-8
Kb = (1.0 x 10^-14 * [H+]) / (3.5 x 10^-8)
To calculate Kb, we need the concentration of [H+]. If the solution is not given, we can assume it to be neutral (pH = 7) for water. In that case, [H+] = 1.0 x 10^-7 M.
Kb = (1.0 x 10^-14 * 1.0 x 10^-7) / (3.5 x 10^-8)
Now you can evaluate this expression using a calculator to find the value of Kb.