A 0.026 kg golf ball moving at 19.6 m/s crashes through the window of a house in 5.6 10-4 s. After the crash, the ball continues in the same direction with a speed of 8.2 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force?p
a = (V-Vo)/t
a=(8.2-19.6)/5.6*10^-4 =-2.04*10^4m/s^2
Fe = m*a=0.025 * (-2.04*10^4=-510 N.= Force exerted.
Correction: Change 0.025 to 0.026 and get 530.4 N.
To find the magnitude of the force exerted on the golf ball, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the golf ball's mass and initial velocity are given, and we need to calculate the force, we can rearrange the equation as:
Force = mass × acceleration
First, let's calculate the acceleration of the golf ball. We can use the formula for average acceleration:
acceleration = (final velocity - initial velocity) / time
Given that the initial velocity of the golf ball is 19.6 m/s, the final velocity after the crash is 8.2 m/s, and the time taken during the crash is 5.6 × 10^-4 seconds, we can substitute these values into the formula to calculate the acceleration.
acceleration = (8.2 - 19.6) / (5.6 × 10^-4)
Now we can calculate the acceleration.
acceleration = -11.4 / (5.6 × 10^-4) (since the ball slowed down, the velocity is negative)
Next, we can calculate the force exerted on the golf ball by multiplying the mass of the ball by its acceleration.
Force = 0.026 kg × (-11.4 / (5.6 × 10^-4))
Calculating this expression will give us the magnitude of the force exerted on the golf ball.