When BaCl2 reacts with Na3PO4, Ba3(PO4)2 and NaCl are formed. Balance the equation and write the coefficients in the blanks.
To balance the equation, we need to ensure that there is an equal number of each type of atom on both sides of the equation. Let's start by writing the unbalanced equation:
BaCl2 + Na3PO4 -> Ba3(PO4)2 + NaCl
We'll begin by balancing the atoms other than oxygen (O) and hydrogen (H) first. In this case, we have barium (Ba), chlorine (Cl), sodium (Na), phosphorus (P), and chlorine (Cl) as the atoms to consider.
1. Start with the elements that appear only once on each side of the equation. In this case, barium (Ba) and sodium (Na) are good candidates. Count the number of each atom on both sides of the equation:
Ba: 1 on the left side, 3 on the right side
Na: 0 on the left side, 1 on the right side
To balance the barium (Ba) atoms, we need to multiply BaCl2 by 3:
3BaCl2 + Na3PO4 -> Ba3(PO4)2 + NaCl
Now the barium (Ba) atoms are balanced.
2. Moving on to the chlorine (Cl) atoms, we have 6 chlorine (Cl) atoms on the left side and 2 chlorine (Cl) atoms on the right side. To balance the chlorine (Cl) atoms, we need to multiply NaCl by 3:
3BaCl2 + Na3PO4 -> Ba3(PO4)2 + 3NaCl
Now the chlorine (Cl) atoms are balanced as well.
3. Next, let's focus on the sodium (Na) atoms. There are 3 sodium (Na) atoms on the left side and 3 sodium (Na) atoms on the right side. Therefore, sodium (Na) atoms are already balanced.
4. Finally, we need to balance the phosphorus (P) atoms. There is 1 phosphorus (P) atom on the left side and 2 phosphorus (P) atoms on the right side. To balance the phosphorus (P) atoms, we need to multiply Na3PO4 by 2:
3BaCl2 + 2Na3PO4 -> Ba3(PO4)2 + 3NaCl
Now all the atoms in the chemical equation are balanced.
Therefore, the balanced equation with coefficients filled in the blanks is:
3BaCl2 + 2Na3PO4 -> Ba3(PO4)2 + 3NaCl