A wire that is 630 m long is perpendicular to a 0.31 T magnetic field. A 1.8 N force acts on the wire. What current is in the wire?
To find the current in the wire, you can use the equation F = BIL, where F is the force, B is the magnetic field, I is the current, and L is the length of the wire.
In this problem, you are given:
- Length of the wire (L) = 630 m
- Magnetic field (B) = 0.31 T
- Force (F) = 1.8 N
You need to find the current (I) in the wire.
Rearranging the equation F = BIL, we can solve for current I:
I = F / (BL)
Substituting the given values:
I = 1.8 N / (0.31 T * 630 m)
First, multiply B by L:
B * L = 0.31 T * 630 m = 194.7 T·m
Now, divide the force by the product of B and L:
I = 1.8 N / 194.7 T·m
Finally, calculate the current:
I ≈ 0.00924 A
Therefore, the current in the wire is approximately 0.00924 Amps.