The distance between a loudspeaker and the left ear of a listener is 2.19 m. (a) Calculate the time required for sound to travel this distance taking the speed of sound to be 343 m/s. (b) Assuming that the sound frequency is 525 Hz, how many wavelengths of sound are contained in this distance?
Damon, I am so lost, could you at least give me a hint so I can show you some work?
t = s/v =2.19/343 = 6.38•10⁻³s
λ =v/f = 343/525 = 0.653 m
N = s/ λ
Thank you Elena .... you are a much better helper than Damon
(a) To calculate the time required for sound to travel a distance, we can use the formula:
Time = Distance / Speed
Given:
Distance = 2.19 m
Speed of sound = 343 m/s
Substituting these values into the formula, we have:
Time = 2.19 m / 343 m/s
Dividing 2.19 m by 343 m/s, we get:
Time ≈ 0.00639 seconds (rounded to 5 decimal places)
Therefore, the time required for sound to travel this distance is approximately 0.00639 seconds.
(b) The formula to calculate the wavelength of sound is:
Wavelength = Speed of sound / Frequency
Given:
Speed of sound = 343 m/s
Frequency = 525 Hz
Substituting these values into the formula, we have:
Wavelength = 343 m/s / 525 Hz
Dividing 343 m/s by 525 Hz, we get:
Wavelength ≈ 0.653 m (rounded to 3 decimal places)
Therefore, the wavelength of sound is approximately 0.653 meters.
To determine how many wavelengths are contained in the 2.19 m distance, we divide the distance by the wavelength:
Number of wavelengths = Distance / Wavelength
Substituting the values, we have:
Number of wavelengths = 2.19 m / 0.653 m
Dividing 2.19 m by 0.653 m, we get:
Number of wavelengths ≈ 3.355
Therefore, there are approximately 3.355 wavelengths of sound contained in the distance of 2.19 meters.