Mr. Rodney's English class is made up of 28 students. He has 6 ESL students, 10 remedial students, and 5 advanced learners. ESL students make up 1/5 of the remedial students and 3/5 of the advanced learners.
1. What is the probability that a student is ESL and remedial?
2. What is the probability that a student is ESL and an advanced learner?
3. What is the probability that a student is remedial and NOT ESL?
I really don't understand how to do any of these...
To answer these questions, we need to calculate the probabilities based on the information given about the number of students and their specific categories. Let's go through each question step by step:
1. What is the probability that a student is ESL and remedial?
To find the probability of a student being both ESL and remedial, we need to determine the number of ESL remedial students and divide it by the total number of students.
Given information:
- Total number of students: 28
- ESL students: 6
- Remedial students: 10
To find the number of students who are both ESL and remedial, we first need to determine the fraction of remedial students who are ESL. The problem states that ESL students make up 1/5 of the remedial students. So, we can calculate this by multiplying the total number of remedial students by 1/5: 10 * 1/5 = 2.
Therefore, the probability of a student being ESL and remedial is 2/28, which can be simplified to 1/14.
2. What is the probability that a student is ESL and an advanced learner?
To determine this probability, we need the number of students who are both ESL and advanced learners, and divide it by the total number of students.
Given information:
- Total number of students: 28
- ESL students: 6
- Advanced learners: 5
The problem states that ESL students make up 3/5 of the advanced learners. So, we can calculate the number of students who are both ESL and advanced by multiplying the total number of advanced learners by 3/5: 5 * 3/5 = 3.
Therefore, the probability of a student being ESL and an advanced learner is 3/28.
3. What is the probability that a student is remedial and NOT ESL?
To determine this probability, we need to find the number of students who are remedial but not ESL and divide it by the total number of students.
Given information:
- Total number of students: 28
- ESL students: 6
- Remedial students: 10
We already calculated that there are 2 students who are both ESL and remedial. Therefore, to find the number of remedial students who are NOT ESL, subtract the number of students who are both ESL and remedial from the total number of remedial students: 10 - 2 = 8.
Hence, the probability of a student being remedial and NOT ESL is 8/28, which can also be simplified to 2/7.
I hope this step-by-step explanation helps you understand the process!