Hydrogen peroxide solution, H2O2(aq), is available with a concentration of 1.667mol/L. When diluted to a concentration of 0.25mol/L, the solution is used as a disinfectant. What volume of water should be added to 100 mL of the concentrated hydrogen peroxide solution to prepare the disinfectant?
And this one too please thx👍
I need help with this too.
Hey Lori and others who would like to know the answer, the formula you should be using in this case would be the Dilution formula.
C1(V1)=C2(V2) (the ones and twos are subscripts).
Once you get the formula all written down, the work should look like this:
C1(V1)=C2(V2)
1.667 mol/L(0.100L)=0.25 mol/L(V2)
0.1667/0.25 = 0.25/0.25(V2)
0.6668 (0.67 significant figures).
Therefore, you would need to add roughly 670 mL of water, or 0.67 L of water to get the 0.25 mol/L dilution you want.
To determine the volume of water needed to dilute the concentrated hydrogen peroxide solution, we can use the equation for dilution. The equation is:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (1.667 mol/L)
V1 = initial volume of the solution (unknown)
C2 = final concentration of the solution (0.25 mol/L)
V2 = final volume of the solution (100 mL + volume of water to be added)
First, rearrange the equation to solve for V1:
V1 = (C2V2) / C1
Now, substitute the given values into the equation:
V1 = (0.25 mol/L * (100 mL + V2)) / 1.667 mol/L
Simplify the equation:
V1 = (0.25 * (100 + V2)) / 1.667
To solve for V1, multiply both sides of the equation by 1.667:
1.667V1 = 0.25 * (100 + V2)
Divide both sides by 1.667:
V1 = (0.25 * (100 + V2)) / 1.667
Now, substitute the given values into the equation and solve for V1:
V1 = (0.25 * (100 + V2)) / 1.667
Since there are no additional given values, we can't solve for V1 in this equation. Please provide the final volume of the solution (V2) or any other relevant information to determine V1.
Let me know if you have any other questions!