how much water at 90 degree fahrenheit must be mixed with 30 gallons of water at 40 degrees fahrenheit so that the resulting temperature of all of the water would be 75 degree fahrenheit
Are we assuming something like
mix 2 L of water at 60° with 2 L of water at 80° we will have 4 L of water at 70° ?
Perhaps a physics teacher could shed some like on this
If this is valid then
90x + 40(30) = 75(x+30)
90x + 1200 = 75x + 2250
15x = 1050
x = 70
70 gallons of the hot water must be added