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prove the following trigonometric identity:
(cos x/(1+sinx))+tanx = secx
1 answer
Write tan(x) as sin(x)/cos(x), add upo the two fractions and you get 1/cos(x) which is sec(x).
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so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
