Before 1986, a gold bullion in the Federal Reserve Bank was rectangular and had a volume of approximately 727.7 cm3. The density of gold is 19.3 g/cm3. A pound is approximately 454 g. Find the weight of one gold bullion to the nearest tenth of a pound.

Mass = Density X Volume

Mass = 727.7 CM^3 X 19.3 g/cm^3
Mass = 14,044.61 g
Since a pound is approximately 454 g

Mass = 14,044.61/454
Mass/weight = 30.9 lbs

30.9 lb

Explanation please

31 305 lbs.

30

315 hfh

To find the weight of one gold bullion, we need to follow these steps:

Step 1: Calculate the mass of one gold bullion.
Since we have the volume and density of gold, we can use the formula:
Density = Mass / Volume

The density of gold is 19.3 g/cm3, and the volume is given as 727.7 cm3.
So, rearranging the formula, we have:
Mass = Density x Volume

Mass = 19.3 g/cm3 x 727.7 cm3 = 14,047.61 g

Step 2: Convert grams to pounds.
To convert from grams to pounds, we need to divide the mass by the conversion factor.
1 pound = 454 g

Weight = 14,047.61 g / 454 g/pound ≈ 30.89 pounds

Therefore, the weight of one gold bullion is approximately 30.9 pounds (rounded to the nearest tenth of a pound).