what is the molarity of a solution of 232 g of NaCl in 2.1 of water?
See your problem with MgF2. It's worked the same way AND technically it can't be solved either. By the way, 2.1 what?
2L of water
To find the molarity (M) of a solution, you need to know the moles of solute (NaCl) and the volume of the solution (water).
Here's how you can calculate the molarity:
1. Determine the moles of NaCl:
- The molar mass of NaCl is 58.44 g/mol (22.99 g/mol for Na + 35.45 g/mol for Cl).
- Divide the mass of NaCl by its molar mass to find the moles: moles = mass / molar mass.
- In this case, moles = 232 g / 58.44 g/mol.
2. Determine the volume of the solution:
- The volume of the solution is given as 2.1 L of water.
3. Calculate the molarity:
- Divide the moles of NaCl by the volume of the solution in liters: M = moles / volume.
- In this case, M = (232 g / 58.44 g/mol) / 2.1 L.
Now you can calculate the molarity of the solution.