Chlorine gas + aqueous sodium bromide --> aqueous bromine + aqueous sodium chloride.
I got:
Cl2+2NaBr2(aq)-> Br2(aq)+2NaCl2(aq)
Is this right ?
No. Sodium bromide is NaBr. Sodium chloride is NaCl.
Almost! The balanced equation for the reaction between chlorine gas (Cl2) and aqueous sodium bromide (NaBr) is:
Cl2 + 2NaBr(aq) → 2NaCl(aq) + Br2(aq)
Here's how you can balance the equation step by step:
1. Start by counting the number of each type of atom on both sides of the equation. On the left side, you have 1 Cl and 2 Na, while on the right side, you have 2 Na, 1 Cl, and 1 Br.
Cl2 + 2NaBr(aq) → 2NaCl(aq) + Br2(aq)
2. To balance the chlorines (Cl), add a coefficient of 2 in front of NaCl and Br2:
Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)
3. Now, count the number of sodium (Na) atoms. We have 2 Na on both sides, so sodium is already balanced.
Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)
4. Finally, count the number of bromine (Br) atoms. We have 2 Br on the left side (from NaBr) and 2 Br on the right side (from Br2), so bromine is balanced as well.
Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)
Therefore, the balanced equation is:
Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)