Show the solutions of the two examples given in the notes. (Hint: Finding a "solution" means solving for all missing sides and angle measures in each triangle.)
(a) If a = 4, b = 3, and A = 36o.
(b) If a = 3, b = 4, and A = 48.59o
(a) use law of sines:
a/sinA = b/sinB
4/.58778 = 3/sinB
sinB = .440
B = 26°
so, C=118°
now figure c
(b) since sin48.59° = 3/4, you have a right triangle. other leg is √7